Step 1: Understanding the Bode diagram.
A Bode diagram is a graphical representation of a system's frequency response. The amplitude ratio (AR) and phase angle ($\phi$) are plotted against the frequency ($\omega$).
Step 2: Explanation of the Bode plot.
- (A) log AR vs log $\omega$ and $\phi$ vs log $\omega$: This is the standard form of a Bode plot.
- (B) log AR vs $\omega$ and log $\phi$ vs log $\omega$: This is incorrect because both AR and $\phi$ are plotted against log $\omega$.
- (C) AR vs log $\omega$ and log $\phi$ vs log: This is incorrect because $\phi$ should be plotted against log $\omega$.
- (D) AR vs $\omega$ and $\phi$ vs $\omega$: This is incorrect as Bode plots are typically log-log plots.
Step 3: Conclusion.
The correct option is (A), as it correctly represents the standard Bode diagram plotting both amplitude and phase against the logarithm of frequency.
Given an open-loop transfer function \(GH = \frac{100}{s}(s+100)\) for a unity feedback system with a unit step input \(r(t)=u(t)\), determine the rise time \(t_r\).
Consider a linear time-invariant system represented by the state-space equation: \[ \dot{x} = \begin{bmatrix} a & b -a & 0 \end{bmatrix} x + \begin{bmatrix} 1 0 \end{bmatrix} u \] The closed-loop poles of the system are located at \(-2 \pm j3\). The value of the parameter \(b\) is: