Question:

\( \binom{7}{0}+\binom{7}{1} + \binom{7}{2}+\binom{7}{3} + \cdots + \binom{7}{7} \)

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Sum of all binomial coefficients of order n equals \(2^n\).
Updated On: May 1, 2026
  • \( 2^8 -2 \)
  • \( 2^7 -1 \)
  • \( 2^7 \)
  • \( 2^8 -1 \)
  • \( 2^7 -2 \)
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The Correct Option is C

Solution and Explanation

Concept: Sum of binomial coefficients.

Step 1:
Recall identity.
\[ \sum_{r=0}^{n} \binom{n}{r} = 2^n \]

Step 2:
Here \( n=7 \).

Step 3:
Substitute: \[ = 2^7 \]

Step 4:
Expand meaning: \[ =128 \]

Step 5:
Final answer: \[ 2^7 \]
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