Question:
Benzonitrile on reduction with stannous chloride in presence of hydrochloric acid followed by acid hydrolysis forms,
Benzonitrile on reduction with stannous chloride in presence of hydrochloric acid followed by acid hydrolysis forms,
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Stephen Reduction: Nitrile + $\text{SnCl}_2$/$\text{HCl} \rightarrow$ Imine $\xrightarrow{\text{H}_3\text{O}^+}$ Aldehyde.
Updated On: May 14, 2026
- Benzal chloride
- Benzoyl chloride
- Benzophenone
- Benzaldehyde
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The Correct Option is D
Solution and Explanation
Step 1: Concept
The reaction described is the Stephen Reaction, used to convert nitriles to aldehydes.
Step 2: Meaning
$\text{SnCl}_2$ and $\text{HCl}$ act as a reducing agent to form an imine intermediate (aldimine).
Step 3: Analysis
Benzonitrile ($\text{C}_6\text{H}_5\text{CN}$) is reduced to benzaldimine ($\text{C}_6\text{H}_5\text{CH=NH} \cdot \text{HCl}$). Subsequent acid hydrolysis of this imine yields the corresponding aldehyde.
Step 4: Conclusion
The final product obtained from the hydrolysis of the benzaldimine intermediate is Benzaldehyde. Final Answer: (D)
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