Question:
Benzaldehyde condenses with N,N-dimethyl aniline in presence of anhydrous ZnCl2 to give:
Benzaldehyde condenses with N,N-dimethyl aniline in presence of anhydrous ZnCl2 to give:
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Malachite is the product when benzaldehyde and N,N-dimethyl aniline react in the presence of anhydrous ZnCl2.
Updated On: Apr 22, 2026
- azo dye
- malachite
- michlers ketone
- buffer yellow
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The Correct Option is B
Solution and Explanation
Step 1: Identifying the reaction.
The reaction involves the condensation of benzaldehyde with N,N-dimethyl aniline in the presence of anhydrous ZnCl2. This is a typical reaction for forming a product known as malachite.
Step 2: Explanation of the products.
- (1) Azo dye: Azo dyes are typically formed from reactions involving diazonium salts, not a condensation of the given reagents.
- (2) Malachite: This is the correct product formed from the condensation of benzaldehyde and N,N-dimethyl aniline in the presence of ZnCl2.
- (3) Michler's ketone: This is a different compound, formed under different conditions, involving dimethylaniline and formaldehyde.
- (4) Buffer yellow: This is not a known product of this condensation reaction.
Step 3: Conclusion.
The correct answer is (2) malachite.
The reaction involves the condensation of benzaldehyde with N,N-dimethyl aniline in the presence of anhydrous ZnCl2. This is a typical reaction for forming a product known as malachite.
Step 2: Explanation of the products.
- (1) Azo dye: Azo dyes are typically formed from reactions involving diazonium salts, not a condensation of the given reagents.
- (2) Malachite: This is the correct product formed from the condensation of benzaldehyde and N,N-dimethyl aniline in the presence of ZnCl2.
- (3) Michler's ketone: This is a different compound, formed under different conditions, involving dimethylaniline and formaldehyde.
- (4) Buffer yellow: This is not a known product of this condensation reaction.
Step 3: Conclusion.
The correct answer is (2) malachite.
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