Question:
Average e.m.f. of 2.4 V is induced in a coil when a current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.4 second. The self inductance of the coil is
Average e.m.f. of 2.4 V is induced in a coil when a current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.4 second. The self inductance of the coil is
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The change in current is from +10 A to -10 A, so it is 20 A in total.
Updated On: Nov 12, 2026
- \(50\text{ mH}\)
- \(48\text{ mH}\)
- \(45\text{ mH}\)
- \(42\text{ mH}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Average induced emf is \(e=L\dfrac{|\Delta I|}{\Delta t}\).
Step 2: Change in current
The current goes from \(+10\text{ A}\) to \(-10\text{ A}\), so \(|\Delta I|=20\text{ A}\).
Step 3: Calculation
\(2.4=L\times\dfrac{20}{0.4}=50L\)
Step 4: Result
\(L=0.048\text{ H}=48\text{ mH}\)
Final Answer:
The self inductance is \(48\text{ mH}\). \[ \boxed{\text{(B) }48\text{ mH}} \]
Average induced emf is \(e=L\dfrac{|\Delta I|}{\Delta t}\).
Step 2: Change in current
The current goes from \(+10\text{ A}\) to \(-10\text{ A}\), so \(|\Delta I|=20\text{ A}\).
Step 3: Calculation
\(2.4=L\times\dfrac{20}{0.4}=50L\)
Step 4: Result
\(L=0.048\text{ H}=48\text{ mH}\)
Final Answer:
The self inductance is \(48\text{ mH}\). \[ \boxed{\text{(B) }48\text{ mH}} \]
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