Question

At what temperature will the rate of effusion of N₂ be 1.625 times that of SO₂ at 50^∘C?

• A. \(110\,\text{K}\)
• B. \(173\,\text{K}\)
• C. \(373\,\text{K}\)
• D. 273K

Hint:

Effusion rate: r ∝ √((T)/(M)) Temperature and molar mass both affect effusion.

Answer 1

The Correct Option is B

Step 1: Graham’s law: (r₁)/(r₂)=√((M₂T₁)/(M₁T₂))
Step 2: Given: fracrN₂rSO₂=1.625, MN₂=28, MSO₂=64, T₂=323K
Step 3: (1.625)²=(64T)/(28×323) ⟹ T ≈ 173K