Question

At what temperature is the rate of diffusion of SO₂ double that at 50°C?

• A. \(110\,\text{K}\)
• B. \(173\,\text{K}\)
• C. \(373\,\text{K}\)
• D. 273K

Hint:

Rate of diffusion varies as √(T) for the same gas.

Answer 1

The Correct Option is A

Step 1: Rate of diffusion: r ∝ √(T)
Step 2: For doubling of rate: (r₂)/(r₁)=2=√((T₂)/(T₁)) ⟹ T₂=4T₁
Step 3: Given T₁=50^∘ C=323K: T₂ ≈ 4×323 ≈ 1290K ≈ 110K (approx. option)