Question

At 300 K, the following graph is obtained for one mole of an ideal gas. If its pressure is 10 atm, then its volume (in L) will be

• A. 0.11
• B. 1.1
• C. 2
• D. 4.0

Hint:

For graphs involving ideal gases, remember that \( P \times V = nRT \). Use slope to relate pressure and volume.

Answer 1

The Correct Option is A

From the graph, slope \( = P \times V = 1.1 \). Given \( P = 10 \text{ atm} \), so: \[ P \times V = 1.1 \Rightarrow V = \frac{1.1}{10} = 0.11 \text{ L} \]