\(V_1\), Volume of \(0.2\ g\) \(H_2\) at \(200\ K\)
\(=\frac { 0.2 \times R \times 200}{2 \times P}\)
\(V_2\), Volume of \(3.0\ g\) of gas A at \(300\ K\)
\(= \frac {0.3 \times R \times 300}{M \times P}\)
Given that, \(V_1 = V_2\)
\(⇒ \frac {0.2 \times R \times 200 }{ 2 \times P} = \frac {0.3 \times R \times 300}{M \times P}\)
\(M = 45\) g mol-1
So, the answer is \(45\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: