Question:
Assertion (A): Sucrose is a non-reducing sugar and does not exhibit mutarotation.
Reason (R): In sucrose, both anomeric carbon atoms are involved in glycosidic bond formation.
Assertion (A): Sucrose is a non-reducing sugar and does not exhibit mutarotation.
Reason (R): In sucrose, both anomeric carbon atoms are involved in glycosidic bond formation.
Reason (R): In sucrose, both anomeric carbon atoms are involved in glycosidic bond formation.
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A sugar is non-reducing when all its anomeric carbon atoms are locked in glycosidic bond formation.
Updated On: Jun 8, 2026
- Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
- Both Assertion and Reason are true, but Reason is not the correct explanation of Assertion.
- Assertion is true, but Reason is false.
- Assertion is false, but Reason is true.
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The Correct Option is A
Solution and Explanation
Concept:
Reducing sugars possess a free anomeric carbon capable of opening into the aldehydic or ketonic form. Mutarotation also requires the presence of a free hemiacetal or hemiketal carbon.
Step 1: Structure of sucrose. Sucrose consists of: \[ \alpha\text{-D-glucose} \] and \[ \beta\text{-D-fructose} \] linked together.
Step 2: Nature of glycosidic linkage. The linkage involves: \[ C_1 \text{ of glucose} \] and \[ C_2 \text{ of fructose} \] which are the anomeric carbon atoms.
Step 3: Reducing property. Since both anomeric carbons participate in bond formation, neither unit can open into a free carbonyl form. Therefore sucrose is non-reducing.
Step 4: Mutarotation. Mutarotation requires interconversion between \(\alpha\) and \(\beta\) forms through the open-chain structure. Because sucrose lacks a free anomeric carbon, mutarotation is not observed.
Step 5: Both Assertion and Reason are correct, and the Reason properly explains the Assertion. \[ \boxed{\text{Option A}} \]
Step 1: Structure of sucrose. Sucrose consists of: \[ \alpha\text{-D-glucose} \] and \[ \beta\text{-D-fructose} \] linked together.
Step 2: Nature of glycosidic linkage. The linkage involves: \[ C_1 \text{ of glucose} \] and \[ C_2 \text{ of fructose} \] which are the anomeric carbon atoms.
Step 3: Reducing property. Since both anomeric carbons participate in bond formation, neither unit can open into a free carbonyl form. Therefore sucrose is non-reducing.
Step 4: Mutarotation. Mutarotation requires interconversion between \(\alpha\) and \(\beta\) forms through the open-chain structure. Because sucrose lacks a free anomeric carbon, mutarotation is not observed.
Step 5: Both Assertion and Reason are correct, and the Reason properly explains the Assertion. \[ \boxed{\text{Option A}} \]
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