Question:

Assertion (A): In $[Ti(H_{2}O)_{6}]^{3+}$ electronic spectra the observed absorption is unsymmetrical appears to be result of more than one absorption bands. Reason (R): Due to Jahn Teller effect energy of $d_{xy}$ is lowered so shown electronic jump $d_{xy}^{1} \rightarrow d_{x^{2}-y^{2}}$ and $d_{xy}^{1} \rightarrow d_{z^{2}}$ so give rise two absorption bands.}

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Unsymmetrical peaks in $d^1, d^4$ (high spin), and $d^9$ complexes are almost always due to Jahn-Teller distortion.
Updated On: May 15, 2026
  • Both (A) and (R) are correct and (R) is the correct explanation of (A)
  • Both (A) and (R) are correct but (R) is NOT the correct explanation of (A)
  • (A) is correct but (R) is not correct
  • (A) is not correct but (R) is correct
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The Correct Option is A

Solution and Explanation


Step 1: Concept
The Jahn-Teller effect describes the geometrical distortion of non-linear molecular systems in electronically degenerate states to remove the degeneracy and lower the energy.

Step 2: Meaning
In $Ti^{3+}$ ($d^1$), the electron occupies the $t_{2g}$ set. This degeneracy causes distortion, splitting both the $t_{2g}$ and $e_g$ levels.

Step 3: Analysis
Instead of a single $t_{2g} \rightarrow e_g$ transition, the splitting leads to multiple closely spaced transitions. This results in an unsymmetrical peak (a shoulder) in the UV-Vis spectrum. The Reason correctly identifies the splitting of orbitals due to this effect.

Step 4: Conclusion
Both statements are correct, and the Jahn-Teller effect is indeed the reason for the unsymmetrical nature of the spectrum. Final Answer: (A)
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