Question:
Assertion (A): Bilaterally symmetrical animals are more efficient in seeking food, locating mate etc.
Reason (R): Cephalization.
Assertion (A): Bilaterally symmetrical animals are more efficient in seeking food, locating mate etc.
Reason (R): Cephalization.
Reason (R): Cephalization.
Show Hint
Cephalization plays a significant role in improving the efficiency of bilaterally symmetrical animals in food seeking, mating, and overall behavior, as it allows better coordination of sensory inputs and motor functions.
Updated On: Mar 18, 2026
- Both A and R are true. R is correct explanation for A
- Both A and R are true. But R is not correct explanation for A
- A is true. But R is false
- A is false. But R is true
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Bilaterally Symmetrical Animals and Cephalization
- Assertion (A): Bilaterally symmetrical animals are more efficient in seeking food and locating mates. (✔ True)
- Reason (R): Cephalization, the concentration of sensory organs and nerve cells in the anterior region, enhances their ability to locate food and mates. (✔ True)
Since both A and R are true, and R correctly explains A, the correct answer is (A).
Was this answer helpful?
0
0
Top AP EAMCET Zoology Questions
- Microanatomy is the study of:
- “Increased diversity contributed to higher productivity”. It was stated by:
- Assertion (A): Kidneys of vertebrates are retroperitoneal organs.
Reason (R): They are covered by the visceral peritoneum only on their ventral side. - Function of oligodendrocytes is:
Match the following types of bones with examples:
View More Questions
Top AP EAMCET Medical Terminology Questions
Match the following medical terms with their correct descriptions or associated organisms:
- In these days, some sports people misuse these drugs.
- An infant is suffering from indigestion. The enzyme lacking is:
- Skull is monoconclyic in
- Identify the correct statement
View More Questions
Top AP EAMCET Questions
- If $\int \cos x . \cos 2x . \cos 5x dx = A \; \sin 2x + B \sin 4x + C \sin 6x + D \sin 8x + k $ (where $k$ is the arbitrary constant of integration), then $\frac{1}{B} + \frac{1}{C} = $
- If $k$ is one of the roots of the equation $x^2 - 25x + 24 = 0 $ such that $A = \begin{bmatrix}1&2&1\\ 3&2&3\\ 1&1&k\end{bmatrix} $ is a non-singular matrix, then $A^{-1}$ =
- If only $\frac{1}{51}^{th}$ ot the main current is to be passed through a galvanometer then the shunt required is $R_1$ and if only $\frac{1}{11}^{th}$ of the main voltage is to be developed across the galvanometer, then the resistance required is $R_2$. Then $\frac{R_2}{R_1} =$
- If $p$ and $q$ are respectively the global maximum and global minimum of the function $f(x) = x^2 e^{2x}$ on the interval $[-2, 2]$ , then $pe^{-4} + qe^4 = $
- If $\displaystyle\sum^n_{k - 1} \tan^{-1} \left( \frac{1}{k^2 + k + 1} \right) = \tan^{-1} (\theta) $ , then $\theta$ =
View More Questions