Question:

Arrange the sweeteners in a sequence based on the degree of sweetness from highest to lowest.
A. Sucrose
B. Saccharin
C. Glucose
D. Dulcin
E. Fructose
Choose the correct answer from the options given below:

Show Hint

Artificial sweeteners are hundreds of times sweeter than natural sugars.
Saccharin (B) and Dulcin (D) must be at the beginning of the sequence.
Glucose (C) is less sweet than sucrose and must be at the end.
  • A, B, D, C, E
  • B, D, E, A, C
  • D, A, C, E, B
  • A, B, C, D, E
Show Solution
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Sweetness is a sensory property of sugars and artificial sweeteners.
The relative sweetness of different compounds is evaluated by comparing them to sucrose (table sugar), which is assigned a reference value of 0 (or 100).

Step 2: Detailed Explanation:

Let us look at the relative sweetness values of the listed sweeteners compared to sucrose:
B. Saccharin: This is an artificial, non-nutritive sweetener.
It is approximately 300 to 500 times sweeter than sucrose.
D. Dulcin: This is an artificial sweetener (an organic compound).
It is approximately 250 times sweeter than sucrose.
E. Fructose: This is the sweetest naturally occurring sugar.
It has a relative sweetness of approximately 2 to 7 times that of sucrose.
A. Sucrose: This is the reference disaccharide, with a relative sweetness of 0.
C. Glucose: This monosaccharide is less sweet than sucrose, with a relative sweetness of approximately 0.7 to 0.
Arraging these from highest to lowest sweetness gives:
Saccharin (B) $>$ Dulcin (D) > Fructose (E) > Sucrose (A) > Glucose (C).
This matches the sequence B, D, E, A, C.

Step 3: Final Answer:

The correct sequence of sweeteners from highest to lowest sweetness is B, D, E, A, C, corresponding to Option (B).
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