Question:
Arrange the following in increasing order of the volume (in L) occupied by them at STP
(i) 1.5 moles of \(CO_2\)
(ii) 14 g of \(N_2\)
(iii) \(10^{21}\) molecules of oxygen
Arrange the following in increasing order of the volume (in L) occupied by them at STP
(i) 1.5 moles of \(CO_2\)
(ii) 14 g of \(N_2\)
(iii) \(10^{21}\) molecules of oxygen
(ii) 14 g of \(N_2\)
(iii) \(10^{21}\) molecules of oxygen
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At STP, just compare moles — volume directly follows.
Updated On: Apr 22, 2026
- (iii) < (ii) < (i)
- (i) < (ii) < (iii)
- (ii) < (i) < (iii)
- (i) < (iii) < (ii)
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The Correct Option is A
Solution and Explanation
Concept:
At STP, volume \( \propto \) number of moles:
\[
1 \text{ mole} = 22.4 \, \text{L}
\]
Step 1: Calculate moles.
(i) \(1.5\) mol
(ii) \( \frac{14}{28} = 0.5 \) mol
(iii) \( \frac{10^{21}}{6.022 \times 10^{23}} \approx \frac{1}{602} \approx 0.00166 \) mol
Step 2: Compare volumes.
\[ 0.00166<0.5<1.5 \]
Step 3: Final order.
\[ (iii)<(ii)<(i) \]
Step 1: Calculate moles.
(i) \(1.5\) mol
(ii) \( \frac{14}{28} = 0.5 \) mol
(iii) \( \frac{10^{21}}{6.022 \times 10^{23}} \approx \frac{1}{602} \approx 0.00166 \) mol
Step 2: Compare volumes.
\[ 0.00166<0.5<1.5 \]
Step 3: Final order.
\[ (iii)<(ii)<(i) \]
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