The area of a sector of a circle is given by the formula:
\[
A = \frac{\theta}{360} \times \pi r^2
\]
where \( \theta \) is the central angle and \( r \) is the radius of the circle.
Here, \( \theta = 60^\circ \) and \( r = 21 \, \text{cm} \).
Substitute the values into the formula:
\[
A = \frac{60}{360} \times \pi \times (21)^2
\]
\[
A = \frac{1}{6} \times \pi \times 441
\]
\[
A = \frac{441 \pi}{6} \approx \frac{441 \times 3.1416}{6} \approx \frac{1385.44}{6} \approx 231 \, \text{cm}^2
\]
Step 2: Conclusion.
Therefore, the area of the sector is approximately \( 231 \, \text{cm}^2 \).
Final Answer:} 231 cm².