Question:
Anisole is treated with HI under two different conditions.
\[
C_6H_5OCH_3 + D \xrightarrow{\text{conc. HI}} A + B
\]
The nature of A and B will be
Anisole is treated with HI under two different conditions.
\[
C_6H_5OCH_3 + D \xrightarrow{\text{conc. HI}} A + B
\]
The nature of A and B will be
Show Hint
In the presence of HI, anisole undergoes nucleophilic substitution, replacing the methoxy group with iodine to form phenol and methyl iodide.
Updated On: Jan 12, 2026
- A and B are \( \text{CH}_3 \) and \( \text{C}_6\text{H}_5\text{OH} \), while C and D are \( \text{CH}_3 \text{I} \) and \( \text{C}_6\text{H}_5\text{I} \)
- A and B are \( \text{C}_6\text{H}_5\text{OH} \) and \( \text{CH}_3 \text{I} \), while C and D are \( \text{CH}_3\text{I} \) and \( \text{C}_6\text{H}_5\text{OH} \)
- A and B are \( \text{C}_6\text{H}_5\text{OH} \) and \( \text{CH}_3 \), while C and D are \( \text{CH}_3\text{I} \) and \( \text{C}_6\text{H}_5\text{I} \)
- Both A and B as well as both C and D are \( \text{CH}_3\text{I} \) and \( \text{C}_6\text{H}_5\text{OH} \)
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The Correct Option is A
Solution and Explanation
Step 1: Nucleophilic Substitution with HI.
In this reaction, anisole undergoes nucleophilic substitution with HI. The methoxy group (\( \text{-OCH}_3 \)) is substituted by the iodine atom, forming \( \text{C}_6\text{H}_5\text{OH} \) (phenol) and \( \text{CH}_3 \text{I} \) (methyl iodide).
Step 2: Conclusion.
The correct answer is (A), as the products are phenol and methyl iodide.
In this reaction, anisole undergoes nucleophilic substitution with HI. The methoxy group (\( \text{-OCH}_3 \)) is substituted by the iodine atom, forming \( \text{C}_6\text{H}_5\text{OH} \) (phenol) and \( \text{CH}_3 \text{I} \) (methyl iodide).
Step 2: Conclusion.
The correct answer is (A), as the products are phenol and methyl iodide.
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