>
Exams
>
Chemistry
>
functional groups
>
aniline reacts with phosgene and koh to form inclu
Question:
Aniline reacts with phosgene and KOH to form:
Show Hint
Phosgene converts amines into isocyanates.
BITSAT - 2014
BITSAT
Updated On:
Mar 24, 2026
Phenol
Benzoyl chloride
Acetanilide
Phenyl isocyanate
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
Step 1:
Aniline reacts with phosgene (\(\mathrm{COCl_2}\)) to form isocyanate intermediate.
Step 2:
In presence of KOH, phenyl isocyanate (\(-\mathrm{NCO}\)) is formed.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on functional groups
The formula of functional group for aldehyde is :
CBSE Class X - 2026
Science
functional groups
View Solution
A medicine compound having an amide linkage was asked. Which of the following compounds contains an amide linkage?
MHT CET - 2025
Chemistry
functional groups
View Solution
Which of the following functional groups is NOT present in Aspartame?
BCECE - 2025
Chemistry
functional groups
View Solution
In the given compound, the number of 2° carbon atom/s is _____.
JEE Main - 2024
Chemistry
functional groups
View Solution
Identify one functional group in the given organic compound O₃.
Bihar Board XII - 2023
Chemistry
functional groups
View Solution
View More Questions
Questions Asked in BITSAT exam
Evaluate the integral \( \int \frac{x}{x^2 + 1} dx \):
BITSAT - 2025
Methods of Integration
View Solution
Evaluate the integral
\( \int_0^1 \frac{\ln(1 + x)}{1 + x^2} \, dx \)
BITSAT - 2025
integral
View Solution
The equation of the line passing through the point $ (2, 3) $ and making equal intercepts on the coordinate axes is:
BITSAT - 2025
Coordinate Geometry
View Solution
If $ x + \frac{1}{x} = 4 $, find the value of $ x^4 + \frac{1}{x^4} $.
BITSAT - 2025
Differential equations
View Solution
If the word "BITS" is coded using \( A=1, B=2, \ldots, Z=26 \), and the code is the sum of the squares of each letter's value, what is the code for the word?
BITSAT - 2025
Algebra
View Solution
View More Questions