Question

Aniline on reaction with Bromine water at room temperature gives:

• A. p - bromoaniline
• B. 2, 4, 6 - Tribromoaniline
• C. m - bromoaniline
• D. o - bromoaniline

Hint:

In electrophilic aromatic substitution, an amine group (-NH2) is an activating group that favors substitution at the ortho and para positions of the benzene ring.

Answer 1

The Correct Option is B

Step 1: Understanding the reaction.
When aniline (C6H5NH2) reacts with bromine water (Br2), it undergoes electrophilic aromatic substitution at the ortho and para positions relative to the amine group (-NH2), due to the activating effect of the amine group. This results in the formation of 2, 4, 6 - Tribromoaniline.
Step 2: Analyzing the options.
(A) p - bromoaniline: Incorrect. This only represents a mono-bromination at the para position, which is not the product of the reaction.
(B) 2, 4, 6 - Tribromoaniline: Correct. The reaction produces a tri-brominated compound, where bromine substitutes at the 2, 4, and 6 positions.
(C) m - bromoaniline: Incorrect. This represents mono-bromination at the meta position, which is less likely due to the activating effect of the amine group.
(D) o - bromoaniline: Incorrect. This is only a single bromination at the ortho position, which is not the final product.
Step 3: Conclusion.
The correct answer is (B) 2, 4, 6 - Tribromoaniline, which is the product of aniline reacting with bromine water.