Question:
An unbiased die is thrown and B is an event showing an odd number on top. Then $P(B)$ is:
An unbiased die is thrown and B is an event showing an odd number on top. Then $P(B)$ is:
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Half the numbers on a standard die are odd, and half are even.
Updated On: Apr 28, 2026
- $\frac{1}{4}$
- $\frac{1}{3}$
- $\frac{1}{6}$
- $\frac{1}{2}$
- $\frac{1}{5}$
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Probability $= \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$.
Step 2: Analysis
Total outcomes $\{1, 2, 3, 4, 5, 6\} = 6$. Favorable outcomes (odd numbers) $\{1, 3, 5\} = 3$.
Step 3: Calculation
$P(B) = \frac{3}{6} = \frac{1}{2}$. Final Answer: (D)
Probability $= \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$.
Step 2: Analysis
Total outcomes $\{1, 2, 3, 4, 5, 6\} = 6$. Favorable outcomes (odd numbers) $\{1, 3, 5\} = 3$.
Step 3: Calculation
$P(B) = \frac{3}{6} = \frac{1}{2}$. Final Answer: (D)
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