Energy conservation in LC circuits ensures smooth oscillations between capacitor and inductor.
Step 1: Use the energy conservation in LC circuits - Maximum energy in capacitor = Maximum energy in inductor: \[ \frac{1}{2} L I_{\text{max}}^2 = \frac{1}{2} \frac{q_{\text{max}}^2}{C}. \]
Step 2: Solve for \(I_{\text{max}}\) - \[ I_{\text{max}} = \frac{q_{\text{max}}}{\sqrt{L C}}. \] Substituting values: \[ I_{\text{max}} = \frac{\sqrt{2.7 \times 10^{-6}}}{\sqrt{75 \times 10^{-3} \cdot 1.2 \times 10^{-6}}}. \] Simplifying: \[ I_{\text{max}} = 9 \times 10^{-3} \, \text{A} = 9 \, \text{mA}. \]
Final Answer: The maximum current in the circuit is 9 mA.
Find output voltage in the given circuit. 

The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 \(\Omega\) is connected across these points is ______ J. 
The given circuit works as: 
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}