Question:

An organic liquid A containing C, H and O with p$K_a$ value 15.9, used in polishing woods, on heating with concentrated sulphuric acid gives a gaseous product B with the empirical formula CH$_2$. B decolourises bromine water as well as dilute permanganate solution. The compound A and B are respectively

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Chemistry Tip: If a gas decolourises bromine water and KMnO$_4$, first suspect an alkene or alkyne due to unsaturation.
Updated On: Apr 27, 2026
  • methanol and methane
  • ethanol and ethane
  • phenol and ethanol
  • ethanol and ethene
  • ethanol and methane
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The Correct Option is D

Solution and Explanation

Concept:
We must identify compound A using all clues:
  • Organic liquid containing C, H, O
  • p$K_a = 15.9$
  • Used in polishing woods
  • On heating with conc. H$_2$SO$_4$ gives gaseous B
  • B has empirical formula CH$_2$
  • B decolourises bromine water and KMnO$_4$
These clues indicate alcohol dehydration producing an alkene.
Step 1: Identify compound A from p$K_a$.
A p$K_a$ around $15.9$ is characteristic of: $$\text{ethanol}$$ because alcohols are weak acids with p$K_a \approx 16$. Also ethanol is commonly used in:
  • polishes
  • varnishes
  • solvents
So A is likely ethanol.
Step 2: Reaction with concentrated sulphuric acid.
When ethanol is heated with conc. H$_2$SO$_4$ at higher temperature, dehydration occurs: $$CH_3CH_2OH \xrightarrow[\Delta]{conc.\ H_2SO_4} CH_2=CH_2 + H_2O$$ So gaseous product B is ethene.
Step 3: Check empirical formula of B.
Ethene molecular formula: $$C_2H_4$$ Empirical formula: $$CH_2$$ Matches the question.
Step 4: Check test with bromine water and KMnO$_4$.
Ethene contains double bond. Therefore it:
  • Decolourises bromine water
  • Decolourises dilute alkaline KMnO$_4$ (Baeyer's test)
So this clue also confirms alkene.
Step 5: Reject other options.
  • Methane / ethane do not decolourise bromine water easily.
  • Phenol does not dehydrate to ethanol.
  • Methanol gives different products.

Step 6: Final answer.
Thus: $$A=\text{ethanol}, \qquad B=\text{ethene}$$ Hence correct option is: $$\boxed{\text{(D)}}$$ :contentReference[oaicite:0]{index=0}
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