Step 1: Understanding the Concept:
The three tests given are characteristic of phenol, \(\text{C}_6\text{H}_5\text{OH}\).
Step 2: Test 1, solubility in NaOH:
Phenol is weakly acidic and reacts with NaOH to form soluble sodium phenoxide. Alcohols, ethers and ketones do not dissolve in NaOH in this way.
Step 3: Test 2, neutral FeCl3:
Phenol gives a violet colour with neutral ferric chloride.
Step 4: Test 3, bromine water:
The -OH group activates the ring, so bromine water gives a white precipitate of 2,4,6-tribromophenol.
Step 5: Conclusion:
The compound is phenol, option D. An alcohol, ether or ketone with formula \(\text{C}_6\text{H}_6\text{O}\) cannot have all three properties.
Final Answer:
The compound is phenol.
\[ \boxed{\text{(D) }\text{Phenol}} \]