Question:
An organic compound with molecular formula $C_5H_{10}O$ does not reduce Tollens’ reagent but forms an addition compound with sodium hydrogen sulphite and gives positive iodoform test. On vigorous oxidation, it gives ethanoic and propanoic acids. The compound is:
An organic compound with molecular formula $C_5H_{10}O$ does not reduce Tollens’ reagent but forms an addition compound with sodium hydrogen sulphite and gives positive iodoform test. On vigorous oxidation, it gives ethanoic and propanoic acids. The compound is:
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Iodoform test confirms presence of methyl ketone group.
Updated On: Apr 24, 2026
- pentan-3-one
- pentanal
- pentan-2-one
- ethoxy ethane
- pentanol
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The Correct Option is C
Solution and Explanation
Concept:
• Tollens’ test → aldehydes
• Iodoform test → methyl ketone ($-COCH_3$)
Step 1: Reject aldehyde
Does not reduce Tollens → not aldehyde
Step 2: Iodoform positive
Contains $-COCH_3$ → methyl ketone
Step 3: Oxidation products
Gives ethanoic + propanoic acids → matches pentan-2-one Final Conclusion:
Option (C)
• Tollens’ test → aldehydes
• Iodoform test → methyl ketone ($-COCH_3$)
Step 1: Reject aldehyde
Does not reduce Tollens → not aldehyde
Step 2: Iodoform positive
Contains $-COCH_3$ → methyl ketone
Step 3: Oxidation products
Gives ethanoic + propanoic acids → matches pentan-2-one Final Conclusion:
Option (C)
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