Question:

An organic compound 'A' (\(\text{C}_{3}\text{H}_{6}\text{O}\)) gives a positive iodoform test but does not reduce Tollens' reagent. Identify the compound 'A':

Show Hint

Not reducing Tollens' reagent means it is not an aldehyde, and the iodoform test needs a methyl ketone group.
Updated On: Nov 12, 2026
  • \(\text{CH}_{3}\text{CH}_{2}\text{CHO}\)
  • \(\text{CH}_{3}\text{CHOHCH}_{3}\)
  • \(\text{CH}_{3}\text{COCH}_{3}\)
  • \(\text{CH}_{3}\text{CH}_{2}\text{CH}_{2}\text{OH}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Tollens' reagent is reduced by aldehydes, and the iodoform test is given by compounds with a \(\text{CH}_{3}\text{CO}-\) group or \(\text{CH}_{3}\text{CH(OH)}-\) group.

Step 2: Use the formula
\(\text{C}_{3}\text{H}_{6}\text{O}\) fits propanal or propanone. The alcohols listed have the formula \(\text{C}_{3}\text{H}_{8}\text{O}\), so they are ruled out.

Step 3: Apply the tests
No reduction of Tollens' reagent rules out propanal. Propanone has a \(\text{CH}_{3}\text{CO}-\) group and gives a positive iodoform test.

Final Answer:
The compound A is acetone, CH3COCH3. \[ \boxed{\text{(C) }\text{CH}_{3}\text{COCH}_{3}} \]
Was this answer helpful?
0
0