An organic compound 'A' has the molecular formula \( C_3H_6O \), it undergoes iodoform test. When saturated with dil. HCl it gives 'B' of molecular formula \( C_9H_{14}O \). A and B respectively are:
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The iodoform test is a chemical reaction that identifies compounds containing a methyl ketone group or a structure that can generate it.
The compound A reacts with iodoform reagent to give a yellow precipitate, confirming the presence of a methyl ketone group. Propanone undergoes this reaction to form mesityl oxide.
Final Answer:
\[
\boxed{\text{Propanone and mesityl oxide}}
\]