Question:
An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives \(NH_3\) gas on heating with NaOH. A can be:
An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives \(NH_3\) gas on heating with NaOH. A can be:
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Urea (\(NH_2CONH_2\)) = 20% C, 46.67% N, 6.67% H, and releases NH\(_3\) with base.
Updated On: Apr 16, 2026
- \(CH_3CONH_2\)
- \(C_6H_5CONH_2\)
- \(NH_2CONH_2\)
- \(CH_3NHCONH_2\)
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The Correct Option is C
Solution and Explanation
Concept:
Compound releasing \(NH_3\) with NaOH suggests an amide or urea derivative. The percentage composition must match the molecular formula.
Step 1: Calculate % composition of each option. Urea (\(NH_2CONH_2\)): Molecular mass = \(14+2+12+16+14+2 = 60\)
• % C = \(\frac{12}{60} \times 100 = 20\%\)
• % N = \(\frac{28}{60} \times 100 = 46.67\%\)
• % H = \(\frac{4}{60} \times 100 = 6.67\%\) This matches exactly with the given data (20% C, 46.66% N, 6.66% H).
Step 2: Check other options.
• (A) \( \mathrm{CH_3CONH_2} \) (acetamide): \( \mathrm{C_2H_5NO} \) → % C $\approx$ 40%, not 20%.
• (B) \( \mathrm{C_6H_5CONH_2} \) (benzamide): \( \mathrm{C_7H_7NO} \) → % C $\approx$ 69%, not 20%.
• (C) \( \mathrm{CH_3NHCONH_2} \) (methylurea): \( \mathrm{C_2H_6N_2O} \) → % C $\approx$ 32%, not 20%.
Step 3: Reaction with NaOH. Urea gives ammonia on heating with NaOH: \[ NH_2CONH_2 + NaOH \xrightarrow{\Delta} Na_2CO_3 + 2NH_3 \uparrow \]
Step 1: Calculate % composition of each option. Urea (\(NH_2CONH_2\)): Molecular mass = \(14+2+12+16+14+2 = 60\)
• % C = \(\frac{12}{60} \times 100 = 20\%\)
• % N = \(\frac{28}{60} \times 100 = 46.67\%\)
• % H = \(\frac{4}{60} \times 100 = 6.67\%\) This matches exactly with the given data (20% C, 46.66% N, 6.66% H).
Step 2: Check other options.
• (A) \( \mathrm{CH_3CONH_2} \) (acetamide): \( \mathrm{C_2H_5NO} \) → % C $\approx$ 40%, not 20%.
• (B) \( \mathrm{C_6H_5CONH_2} \) (benzamide): \( \mathrm{C_7H_7NO} \) → % C $\approx$ 69%, not 20%.
• (C) \( \mathrm{CH_3NHCONH_2} \) (methylurea): \( \mathrm{C_2H_6N_2O} \) → % C $\approx$ 32%, not 20%.
Step 3: Reaction with NaOH. Urea gives ammonia on heating with NaOH: \[ NH_2CONH_2 + NaOH \xrightarrow{\Delta} Na_2CO_3 + 2NH_3 \uparrow \]
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