Step 1: Use the relation between power and focal length.
The power \(P\) of a lens is related to its focal length \(f\) by
\[
P=\frac{1}{f},
\]
where \(f\) is measured in metres.
Step 2: Substitute the given power.
Given,
\[
P=+2\ \text{D}.
\]
Therefore,
\[
f=\frac{1}{P}.
\]
\[
f=\frac{1}{2}.
\]
\[
f=0.5\ \text{m}.
\]
Step 3: Convert into centimetres.
\[
f=0.5\times100.
\]
\[
f=50\ \text{cm}.
\]
Since the power is positive, the lens is a convex lens.
Step 4: Final conclusion.
Therefore, the focal length of the convex lens is
\[
\boxed{50\ \text{cm}}
\]
Hence, the correct option is
\[
\boxed{(2)}
\]