An observer on the top of a tree finds the angle of depression of a car moving towards the tree to be 30^∘. After 3 minutes this angle becomes 60^∘. After how much more time will the car reach the tree?
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In angle of elevation/depression problems, use tanθ=fracheightdistance.
Step 1: Let the height of the tree be h.
Initial distance:
x = (h)/(tan 30^∘) = √(3)h
After 3 minutes:
y = (h)/(tan 60^∘) = frach√(3)
Step 2: Distance covered in 3 minutes:
√(3)h - frach√(3) = \frac2h√(3)
Step 3: Speed:
v = \frac2h3√(3)
Step 4: Remaining distance:
frach√(3)
Step 5: Time required:
t = frach/√(3)2h/(3√(3)) = (3)/(2) = 1.5 min