Step 1: Field observed in the rest frame of the charge.
A stationary point charge produces only an electric field.
Thus, in the frame where the charge is at rest,
\[
\vec{B}=0,
\]
and
\[
\vec{E}\neq 0.
\]
Therefore, an observer initially at rest experiences only the electric field.
Step 2: Consider the observer moving away from the charge.
When the observer starts moving, the charge appears to be moving relative to the observer.
According to the theory of special relativity, electric and magnetic fields transform into one another when viewed from different inertial frames.
A moving charge constitutes an electric current and hence produces a magnetic field in the observer's frame.
Step 3: Fields in the moving observer's frame.
Since the charge is now seen as moving,
\[
\vec{E}'\neq 0
\]
and
\[
\vec{B}'\neq 0.
\]
Thus, the observer experiences both electric and magnetic fields simultaneously.
Step 4: Final conclusion.
Therefore, a moving observer experiences
\[
\boxed{\text{Electric and magnetic fields}}
\]
Hence, the correct option is
\[
\boxed{(3)}
\]