Step 1: Understanding the Concept
A maximum occurs where the path difference is a whole number of wavelengths: \(\Delta = n\lambda\).
Step 2: Path difference
Source B is at the origin, A is at \((0, 4\lambda)\) and the detector is at \((x, 0)\).
\(\Delta = \sqrt{x^{2}+16\lambda^{2}} - x\).
Step 3: Range of the path difference
At \(x = 0\), \(\Delta = 4\lambda\). As \(x \rightarrow \infty\), \(\Delta \rightarrow 0\). It decreases steadily in between.
Step 4: Counting the maxima
Both end points are excluded, so \(0 \lt \Delta \lt 4\lambda\). Hence \(n = 1, 2, 3\), and each value occurs at exactly one point.
There are 3 maxima.
Final Answer:
Exactly 3 points on the positive X-axis show maxima.
\[ \boxed{\text{(A) }3} \]