Question:
An inductor of 200 \(\mu\)H is connected to an alternating source of frequency 50 Hz. Then the inductive reactance is:
An inductor of 200 \(\mu\)H is connected to an alternating source of frequency 50 Hz. Then the inductive reactance is:
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Inductive reactance depends linearly on frequency: \(X_L = 2 \pi f L\). Convert microhenry to henry before calculation.
Updated On: Jun 19, 2026
- \(6.28 \times 10^{-2}~\Omega\)
- \(1.64 \times 10^{-2}~\Omega\)
- \(3.14 \times 10^{-2}~\Omega\)
- \(4.82 \times 10^{-2}~\Omega\)
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The Correct Option is A
Solution and Explanation
Step 1: Formula for inductive reactance.
\[ X_L = 2 \pi f L \] where \(L = 200~\mu\text{H} = 200 \times 10^{-6}~\text{H}\), \(f = 50~\text{Hz}\).
Step 2: Substitute values.
\[ X_L = 2 \pi (50) (200 \times 10^{-6}) = 6.28 \times 10^{-2}~\Omega \]
Step 3: Conclusion.
The inductive reactance is \(6.28 \times 10^{-2}~\Omega\).
\[ X_L = 2 \pi f L \] where \(L = 200~\mu\text{H} = 200 \times 10^{-6}~\text{H}\), \(f = 50~\text{Hz}\).
Step 2: Substitute values.
\[ X_L = 2 \pi (50) (200 \times 10^{-6}) = 6.28 \times 10^{-2}~\Omega \]
Step 3: Conclusion.
The inductive reactance is \(6.28 \times 10^{-2}~\Omega\).
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