Question:

An ideal refrigerator has a freezer at a temperature of 130C. The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) is

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Always convert temperatures to Kelvin before using thermodynamic formulas.
Updated On: Mar 18, 2026
  • 320C
  • 39C
  • 325K
  • 325C
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The Correct Option is B

Solution and Explanation


Step 1:
COP of refrigerator: COP=(TL)/(TH-TL)
Step 2:
TL=130+273=403K, COP = 5
Step 3:
5=(403)/(TH-403) TH=442K=39C
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