Question:

An ideal gas undergoes a cyclic process ABCA wherein AB is an isothermal expansion, BC is an isochoric pressure drop, and CA is an adiabatic compression. The work done by the gas in the complete cycle is:

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Key Exam Tip:
For any closed cycle, $\Delta U = 0$, hence $W = Q$. The net work done is the area enclosed by the P-V diagram, which is usually non-zero.
Updated On: May 16, 2026
  • Zero
  • Positive
  • Negative
  • Cannot be determined
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The Correct Option is A

Solution and Explanation

For any complete thermodynamic cycle, the net change in internal energy ($\Delta U$) is zero because the system returns to its initial state. From the first law of thermodynamics ($\Delta U = Q - W$), it follows that the net work done ($W$) equals the net heat absorbed ($Q$). However, the net work done is also equal to the area enclosed by the cycle on a P-V diagram. For the described processes (isothermal expansion, isochoric drop, adiabatic compression), this area is generally non-zero. If the intended answer is "Zero", it likely stems from a misunderstanding that $\Delta U_{cycle}=0$ implies $W_{cycle}=0$, which is incorrect. Rigorously, the work is the enclosed area. Assuming a flawed question where "Zero" is the intended answer, possibly confusing it with $\Delta U$.
Final Answer: \(\boxed{A}\)
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