Question:

An error of 1 % in measuring head (H) will produce

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The percentage error in discharge is simply the exponent of the head \(H\) multiplied by the percentage error in the head measurement.
Since the exponent for a triangular weir is 2.5 and for a rectangular weir is 1.5, the triangular weir will always exhibit a higher percentage error.
  • Same error in discharge over a rectangular weir and triangular weir
  • More error in discharge over triangular weir compared to rectangular weir
  • More error in discharge over rectangular weir compared to triangular weir
  • No error in discharge over a rectangular weir and triangular weir
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Discharge over weirs depends on the measured head of the water flowing over them.
An error in measuring the head propagates to the calculated discharge based on the power relation between discharge and head.

Step 2: Key Formula or Approach:
For a rectangular weir, the discharge \(Q_r\) is given by:
\[ Q_r \propto H^{3/2} \] For a triangular weir (V-notch), the discharge \(Q_t\) is given by:
\[ Q_t \propto H^{5/2} \]

Step 3: Detailed Explanation:
Let us use differential approximation to calculate the relative error in discharge for both cases:
For the rectangular weir:
\[ \ln(Q_r) = \frac{3}{2} \ln(H) + \text{constant} \] Differentiating both sides:
\[ \frac{dQ_r}{Q_r} = 1.5 \frac{dH}{H} \] Thus, a 1 % error in measuring head (\(\frac{dH}{H} = 1\%\)) produces a 1.5 % error in the calculated rectangular weir discharge.
For the triangular weir:
\[ \ln(Q_t) = \frac{5}{2} \ln(H) + \text{constant} \] Differentiating both sides:
\[ \frac{dQ_t}{Q_t} = 2.5 \frac{dH}{H} \] Thus, a 1 % error in measuring head (\(\frac{dH}{H} = 1\%\)) produces a 2.5 % error in the calculated triangular weir discharge.
Comparing the two, the error in the discharge of a triangular weir (2.5 %) is higher than that of a rectangular weir (1.5 %).

Step 4: Final Answer:
The correct option is 2, which corresponds to "More error in discharge over triangular weir compared to rectangular weir".
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