Step 1: Understanding the Concept
For a prism, \(i + e = A + \delta\).
For one deviation there are two possible incidence angles, and the emergence angle for one equals the incidence angle for the other.
Step 2: Sum of the Two Incidence Angles
For an equilateral prism \(A = 60^{\circ}\) and \(\delta = 45^{\circ}\).
So \(i_1 + i_2 = 60^{\circ} + 45^{\circ} = 105^{\circ}\).
Step 3: Use the Given Difference
The two angles differ by \(20^{\circ}\), so \(i_1 - i_2 = 20^{\circ}\).
Step 4: Calculation
Adding the two equations, \(2i_1 = 125^{\circ}\), so \(i_1 = 62.5^{\circ}\).
Then \(i_2 = 42.5^{\circ}\).
Step 5: Compare the options
Only \(62.5^{\circ}\) appears among the options.
Final Answer:
One of the angles of incidence is 62.5 degrees.
\[ \boxed{\text{(A) }62.5^{\circ}} \]