Question:

An electron is moving with initial velocity \(\vec{v}=a\hat{k}\) in a magnetic field \(\vec{B}=b\hat{j}\). Its de-Broglie wavelength will

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The magnetic force does no work, so the speed and hence the wavelength remain constant.
Updated On: Nov 12, 2026
  • decrease and increase periodically.
  • increase with time.
  • decrease with time.
  • remain constant.
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
de Broglie wavelength: \(\lambda=\dfrac{h}{mv}\).

Step 2: Magnetic force
\(\vec{F}=q(\vec{v}\times\vec{B})\) is always perpendicular to velocity, so it does no work.

Step 3: Result
The speed stays constant, so \(\lambda\) stays constant.

Final Answer:
The de Broglie wavelength remains constant. \[ \boxed{\text{(D) }\text{remain constant}} \]
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