Question:
An aeroplane having a wing span of 30 m flies due north with the speed of 170 m/s. Magnetic field \(B = 3.6\times 10^{-5}\) T. The potential difference between the tips of the wings will be
An aeroplane having a wing span of 30 m flies due north with the speed of 170 m/s. Magnetic field \(B = 3.6\times 10^{-5}\) T. The potential difference between the tips of the wings will be
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The wing tips behave as the ends of a rod moving across the field: emf = B l v.
Updated On: Oct 1, 2026
- \(136.4\) mV
- \(183.6\) mV
- \(272.8\) mV
- \(367.2\) mV
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
A conductor of length \(l\) moving with velocity \(v\) perpendicular to a magnetic field \(B\) develops a motional emf \(\varepsilon=Blv\). The wings act as such a rod.
Step 2: Substitute
\[ \varepsilon=3.6\times10^{-5}\times30\times170 \]
\[ =3.6\times10^{-5}\times5100=0.1836\ \text{V} \]
\[ =183.6\ \text{mV} \]
Step 3: Check the options
The value 136.4 mV and 272.8 mV come from a different product. 367.2 mV is twice the correct value and would come from using a wing span of 60 m. The answer is 183.6 mV, option (B).
Final Answer:
The emf is B l v = 3.6e-5 x 30 x 170 = 0.1836 V, option (B). \[ \boxed{183.6\ \text{mV}} \]
A conductor of length \(l\) moving with velocity \(v\) perpendicular to a magnetic field \(B\) develops a motional emf \(\varepsilon=Blv\). The wings act as such a rod.
Step 2: Substitute
\[ \varepsilon=3.6\times10^{-5}\times30\times170 \]
\[ =3.6\times10^{-5}\times5100=0.1836\ \text{V} \]
\[ =183.6\ \text{mV} \]
Step 3: Check the options
The value 136.4 mV and 272.8 mV come from a different product. 367.2 mV is twice the correct value and would come from using a wing span of 60 m. The answer is 183.6 mV, option (B).
Final Answer:
The emf is B l v = 3.6e-5 x 30 x 170 = 0.1836 V, option (B). \[ \boxed{183.6\ \text{mV}} \]
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