Step 1: Understanding the Concept
For two thin lenses in contact to be achromatic, the condition is
\(\dfrac{\omega_1}{f_1}+\dfrac{\omega_2}{f_2}=0\), that is \(\omega_1P_1+\omega_2P_2=0\).
Step 2: Find the Power of the Second Lens
Total power \(P=P_1+P_2=2\ \text{D}\) and \(P_1=+5\ \text{D}\).
\(P_2=2-5=-3\ \text{D}\)
Step 3: Calculation
\(\dfrac{\omega_1}{\omega_2}=-\dfrac{P_2}{P_1}=-\dfrac{-3}{5}=\dfrac{3}{5}\)
Step 4: Compare the options
The ratio of dispersive powers of convergent to divergent lens is \(3:5\), option (B).
Final Answer:
The dispersive powers of the convergent and divergent lenses are in the ratio 3 to 5.
\[ \boxed{\text{(B) }3:5} \]