Question:
An a.c. source is connected to a capacitor 'C'. Due to increase in its operating frequency
An a.c. source is connected to a capacitor 'C'. Due to increase in its operating frequency
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Capacitive reactance falls as frequency rises, so the peak current rises.
Updated On: Nov 12, 2026
- capacitive reactance increases.
- capacitive reactance remains constant.
- peak current increases.
- peak current decreases.
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Capacitive reactance is \(X_C=\dfrac{1}{2\pi fC}\), which is inversely proportional to frequency.
Step 2: Peak current
\(I_0=\dfrac{V_0}{X_C}=2\pi fCV_0\)
Step 3: Effect of higher frequency
As \(f\) increases, \(X_C\) decreases and \(I_0\) increases.
Final Answer:
Increasing the frequency raises the peak current. \[ \boxed{\text{(C) }\text{peak current increases.}} \]
Capacitive reactance is \(X_C=\dfrac{1}{2\pi fC}\), which is inversely proportional to frequency.
Step 2: Peak current
\(I_0=\dfrac{V_0}{X_C}=2\pi fCV_0\)
Step 3: Effect of higher frequency
As \(f\) increases, \(X_C\) decreases and \(I_0\) increases.
Final Answer:
Increasing the frequency raises the peak current. \[ \boxed{\text{(C) }\text{peak current increases.}} \]
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