Question:
Among the following, the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by:
Among the following, the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by:
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The degree of paramagnetism is determined by the number of unpaired electrons in the electron configuration.
Updated On: Mar 25, 2026
- \( \text{MnSO}_4 \cdot 4\text{H}_2\text{O} \)
- \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \)
- \( \text{FeSO}_4 \cdot 6\text{H}_2\text{O} \)
- \( \text{NiSO}_4 \cdot 6\text{H}_2\text{O} \)
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The Correct Option is D
Solution and Explanation
Step 1: Paramagnetism and electron configuration.
Paramagnetism is due to the presence of unpaired electrons. \( \text{Ni}^{2+} \) has a lower number of unpaired electrons compared to other metal ions in the given compounds, leading to the lowest paramagnetism.
Thus, the correct answer is (4).
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