Question:

According to Wien's displacement law, how is the surface temperature of a star related to its maximum intensity wavelength?

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Remember: Hotter object → shorter wavelength ($\lambda_{\text{max}} \downarrow$).
Updated On: Mar 17, 2026
  • $\lambda_{\text{max}} \propto T$
  • $\lambda_{\text{max}} \propto \frac{1}{T}$
  • $\lambda_{\text{max}} \propto T^2$
  • $\lambda_{\text{max}} \propto \frac{1}{T^2}$
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The Correct Option is B

Solution and Explanation

Concept: Wien's displacement law relates the temperature of a black body to the wavelength at which it emits maximum radiation.
Step 1: Wien's law formula.
\[ \lambda_{\text{max}} T = b \] where $b$ is Wien's constant.
Step 2: Rewriting the relation.
\[ \lambda_{\text{max}} = \frac{b}{T} \]
Step 3: Understanding the relationship.
As temperature increases, the peak wavelength decreases.
Step 4: Evaluating the options.
  • $\lambda_{\text{max}} \propto T$ $\rightarrow$ Incorrect
  • $\lambda_{\text{max}} \propto \frac{1}{T}$ $\rightarrow$ Correct
  • $\lambda_{\text{max}} \propto T^2$ $\rightarrow$ Incorrect
  • $\lambda_{\text{max}} \propto \frac{1}{T^2}$ $\rightarrow$ Incorrect

Step 5: Conclusion.
Thus, $\lambda_{\text{max}}$ is inversely proportional to temperature.
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