Question:

According to VSEPR theory, the molecular shapes of \(XeF_4\), \(XeO_4\), \(XeO_2F_2\) and \(XeOF_4\) respectively are

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Always count lone pairs on central atom — they decide shape distortion.
Updated On: Apr 22, 2026
  • square planar, square planar, see-saw, square pyramidal.
  • square planar, tetrahedral, trigonal bipyramidal, octahedral.
  • square planar, tetrahedral, see-saw, square pyramidal.
  • octahedral, tetrahedral, trigonal bipyramidal, octahedral.
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The Correct Option is C

Solution and Explanation

Concept: Use VSEPR theory: count bond pairs and lone pairs.

Step 1:
\(XeF_4\)
AX\(_4\)E\(_2\) $\longrightarrow$ square planar

Step 2:
\(XeO_4\)
AX\(_4\) $\longrightarrow$ tetrahedral

Step 3:
\(XeO_2F_2\)
AX\(_4\)E $\longrightarrow$ see-saw

Step 4:
\(XeOF_4\)
AX\(_5\)E $\longrightarrow$ square pyramidal
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