Question:

According to the VSEPR theory, the shape of ClO$_3^-$ would be

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When a central atom has 3 bond pairs and 1 lone pair (like NH$_3$ or ClO$_3^-$), the shape is always pyramidal because the lone pair pushes the bonding pairs downward.
Updated On: May 1, 2026
  • Linear
  • Triangular planar
  • Pyramidal
  • Square planar
  • Angular
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The Correct Option is C

Solution and Explanation

Concept: The Valence Shell Electron Pair Repulsion (VSEPR) theory predicts the geometry of molecules based on the repulsion between electron pairs (bonding and lone pairs) around a central atom.

Step 1:
{Determine the valence electrons and steric number.}
Chlorine (Cl) is the central atom with 7 valence electrons. The negative charge adds 1 electron, totaling 8. In ClO$_3^-$, Chlorine forms bonds with three Oxygen atoms.

Step 2:
{Identify bonding and lone pairs.}
Chlorine uses 6 electrons to form three double bonds with Oxygen (in its expanded octet state) and retains 2 electrons as one lone pair.
• Number of bond pairs (or sigma bonding sites) = 3
• Number of lone pairs = 1
• Steric Number = 3 + 1 = 4

Step 3:
{Predict the shape.}
A steric number of 4 corresponds to a tetrahedral electron geometry. However, with one lone pair, the molecular shape is distorted to minimize repulsion. The resulting arrangement of atoms is pyramidal.
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