Question:

\(AB\) is a diameter of a circle and \(C\) is any point on the circumference of the circle. Then

Show Hint

Angle in semicircle is \(90^\circ\). Area = \(\frac{1}{2} \times \text{base} \times \text{height}\).
Updated On: Apr 23, 2026
  • The area of \(\Delta ABC\) is maximum when it is isosceles
  • The area of \(\Delta ABC\) is minimum when it is isosceles
  • The perimeter of \(\Delta ABC\) is minimum when it is isosceles
  • None of these
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Formula / Definition}
\[ \text{Area} = \frac{1}{2} \cdot AB \cdot h \]
Step 2: Calculation / Simplification}
\(AB = d\) (constant). Height \(h = AC \sin \angle CAB\)
Maximum area when \(h\) is maximum
\(h\) maximum when \(C\) is at highest point (perpendicular to \(AB\))
At this point, \(AC = BC \Rightarrow\) isosceles right triangle.
Step 3: Final Answer
\[ \text{The area of } \Delta ABC \text{ is maximum when it is isosceles} \]
Was this answer helpful?
0
0