Given: Original weft yarn: 24 tex, pick density = 25/cm New weft yarn: 6 tex (same packing density)
Key Concepts: Yarn diameter ($d$) $\propto \sqrt{{tex}}$ To maintain fabric cover: $\frac{d}{{spacing}}$ must stay constant Spacing ($s$) = $\frac{1}{{pick density}}$
Step 1: Find Yarn Diameter Ratio \[ \frac{d_2}{d_1} = \sqrt{\frac{6}{24}} = \sqrt{\frac{1}{4}} = \frac{1}{2} \] New yarn is half the diameter of original.
Step 2: Maintain Fabric Cover \[ \frac{d_1}{s_1} = \frac{d_2}{s_2} \implies d_1 P_1 = d_2 P_2 \] \[ P_2 = P_1 \times \frac{d_1}{d_2} = 25 \times 2 = 50 \] Final Answer: \[ \boxed{50} \]
| Group I | Group II |
| P. Rotor spinning | 1. Twistless parallel fibres in core and helically arranged filament on surface |
| Q. Air-jet spinning | 2. Helically twisted core and distinct wrappers on surface |
| R. Wrap spinning | 3. Multifilament core covered by staple fibres stuck to molten polymer |
| S. Bobtex spinning | 4. Twistless core wrapped regularly and helically by thin fibre ribbons |