



Force Acting on the Block:
The force \( F \) acting on the block increases linearly with time \( t \).
We can write:
\[ F = kt \] where \( k \) is a constant of proportionality.
Using Newton's Second Law to Find Acceleration:
According to Newton's second law, the acceleration \( a \) of the block is given by:
\[ F = ma \]
Substituting \( F = kt \):
\[ ma = kt \implies a = \frac{kt}{m} \]
where \( m \) is the mass of the block.
Relation Between Acceleration and Time:
From the equation \( a = \frac{kt}{m} \), we see that the acceleration \( a \) is directly proportional to time \( t \).
This means that as time \( t \) increases, the acceleration \( a \) also increases linearly.
Conclusion:
The correct graph representing the acceleration of the block with time is a straight line passing through the origin, as shown in Option (2).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)