Question:

A wire carrying current I has the shape as shown in the adjoining figure. Linear parts of the wire are very long and parallel to X–axis while the semicircular portion of radius R lies in the Y-Z plane. Magnetic field at point O is: 

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Use right–hand thumb rule separately for curved and straight current elements.
Updated On: Mar 20, 2026
  • \(\vec{B}=\dfrac{\mu_0 I}{4\pi R}(\pi \hat{i}\times 2\hat{k})\)
  • \(\vec{B}=\dfrac{\mu_0 I}{4\pi R}(\pi \hat{i}+2\hat{k})\)
  • \(\vec{B}=\dfrac{\mu_0 I}{4\pi R}(\pi \hat{i}-2\hat{k})\)
  • vecB=(mu₀ I)/(4π R)(hati+2hatk)
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The Correct Option is B

Solution and Explanation


Step 1:
Magnetic field due to semicircular arc: Bₐrc=(mu₀ I)/(4R) Direction is along +hati.
Step 2:
Magnetic field due to two long straight wires: Bₛtᵣₐᵢght=2((mu₀ I)/(4π R)) Direction is along +hatk.
Step 3:
Net magnetic field: vecB=(mu₀ I)/(4π R)(π hati+2hatk)
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