Question:
A wheat crop grown on two hectare area produced 10 ton grain and required 5 irrigations of 6 cm each, find out its field water use efficiency:
A wheat crop grown on two hectare area produced 10 ton grain and required 5 irrigations of 6 cm each, find out its field water use efficiency:
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WUE = Yield (Area \(\times\) Water applied).
Convert cm to mm (1 cm = 10 mm).
Higher WUE means better water use.
Convert cm to mm (1 cm = 10 mm).
Higher WUE means better water use.
Updated On: Aug 18, 2026
- 33 kg/ha-mm
- 16.67 kg/ha-mm
- 3.33 kg/ha-mm
- 1.67 kg/ha-mm
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Field water use efficiency (WUE) relates yield to water applied.
It is expressed as kg grain per ha-mm of water.
Step 2: Key Formula or Approach:
WUE = Yield (kg) (Area (ha) \(\times\) Water applied (mm)).
Water applied = Number of irrigations \(\times\) Depth of each irrigation.
Step 3: Detailed Explanation:
Yield = 10 ton = 10,000 kg.
Area = 2 ha.
Water applied = 5 irrigations \(\times\) 6 cm = 30 cm = 300 mm.
WUE = 10,000 (2 \(\times\) 300) = 10,000 600 = 16.67 kg/ha-mm.
Step 4: Final Answer:
The field water use efficiency is 16.67 kg/ha-mm.
Hence, the correct option is (B).
Field water use efficiency (WUE) relates yield to water applied.
It is expressed as kg grain per ha-mm of water.
Step 2: Key Formula or Approach:
WUE = Yield (kg) (Area (ha) \(\times\) Water applied (mm)).
Water applied = Number of irrigations \(\times\) Depth of each irrigation.
Step 3: Detailed Explanation:
Yield = 10 ton = 10,000 kg.
Area = 2 ha.
Water applied = 5 irrigations \(\times\) 6 cm = 30 cm = 300 mm.
WUE = 10,000 (2 \(\times\) 300) = 10,000 600 = 16.67 kg/ha-mm.
Step 4: Final Answer:
The field water use efficiency is 16.67 kg/ha-mm.
Hence, the correct option is (B).
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