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a vessel has 6 gram of hydrogen at pressure p and
Question:
A vessel has \(6\) gram of hydrogen at pressure \(P\) and temperature \(500\) K. A small hole is made in it so that hydrogen leaks out. How much hydrogen leaks out if the final pressure is \(\frac{P}{2}\) and the temperature falls to \(300\) K?
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The vessel volume is fixed, so $n\propto P/T$.
MHT CET - 2026
MHT CET
Updated On:
Oct 1, 2026
\(2\) gram
\(3\) gram
\(4\) gram
\(1\) gram
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Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
Step 1: Use the gas equation
\(PV=nRT\) with fixed \(V\) gives \(n\propto\frac{P}{T}\).
Step 2: Ratio
\(\frac{n_2}{n_1}=\frac{P/2}{300}\times\frac{500}{P}=\frac{5}{6}\).
Step 3: Mass left and lost
Mass left \(=\frac56\times6=5\) g, so \(6-5=1\) g leaks out. Option (D).
Final Answer:
One gram of hydrogen leaks out, option (D). \[ \boxed{\text{(D) }1\text{ g}} \]
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