Question:

A vessel has \(6\) gram of hydrogen at pressure \(P\) and temperature \(500\) K. A small hole is made in it so that hydrogen leaks out. How much hydrogen leaks out if the final pressure is \(\frac{P}{2}\) and the temperature falls to \(300\) K?

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The vessel volume is fixed, so $n\propto P/T$.
Updated On: Oct 1, 2026
  • \(2\) gram
  • \(3\) gram
  • \(4\) gram
  • \(1\) gram
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The Correct Option is D

Solution and Explanation

Step 1: Use the gas equation
\(PV=nRT\) with fixed \(V\) gives \(n\propto\frac{P}{T}\).

Step 2: Ratio
\(\frac{n_2}{n_1}=\frac{P/2}{300}\times\frac{500}{P}=\frac{5}{6}\).

Step 3: Mass left and lost
Mass left \(=\frac56\times6=5\) g, so \(6-5=1\) g leaks out. Option (D).

Final Answer:
One gram of hydrogen leaks out, option (D). \[ \boxed{\text{(D) }1\text{ g}} \]
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