A vessel containing 1 more of \( O_2 \) gas (molar mass 32) at temperature \( T \). The pressure of the gas is \( p \). An identical vessel containing one mole of He gas (molar mass 4) at temperature 2T has a pressure of â
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The pressure of an ideal gas is directly proportional to the number of moles and temperature, according to the ideal gas law.
Step 1: Use the ideal gas law.
Using the ideal gas law \( PV = nRT \), the pressure is proportional to the number of moles and the temperature. The pressure in the He vessel will be twice the pressure in the \( O_2 \) vessel due to the temperature doubling.
Step 2: Conclusion.
The pressure in the He vessel will be \( 2p \).
Final Answer:
\[
\boxed{2p}
\]